Question

a 5M solution of h2so4 is diluted from 1lit to a volume of 100 lit ,the normality

Answer 1

M1 x V1=M2 x V2
5x1=M2 x 100
M2 = 1/20
Normality= N-FACTOR x M2
                =1/20x2=0.1

Answer 2

Answer: The normality of the diluted solution of sulfuric acid is 0.1 N

Explanation:

• The relation between normality and molarity follows:

$N=nM$

where,

N = normality of solution

n = n-factor of solution

M = molarity of solution

We are given:

Molarity of $H_2SO_4$ solution = 5 M

n-factor of $H_2SO_4$ solution = 2 (there are 2 replaceable hydrogen ions)

Putting values in above equation, we get:

$N=2\times 5=10N$

• To calculate the normality of the diluted solution, we use the equation:

$N_1V_1=N_2V_2$

where,

$N_1\text{ and }V_1$ are the normality and volume of the concentrated solution

$N_2\text{ and }V_2$ are the normality and volume of diluted solution

We are given:

$N_1=10N\\V_1=1L\\N_2=?N\\V_2=100L$

Putting values in above equation, we get:

$10\times 1=N_2\times 100\\\\N_2=0.1N$

Hence, the normality of the diluted solution of sulfuric acid is 0.1 N