a 5m wide Lane was paved with bricks of size 20 CM by 15 CM. if the rate of bricks was 750Rs per 1000 and if bricks s worth 49500rs were used, find the length of lane
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width of the lane=5m=500cm.
if 1000 bricks cost Rs. 750
then 1 brick costs 750/1000=Rs. 0.75
if total bricks used cost Rs. 49500.
then no. of bricks used
= cost of total no. of bricks used/cost of 1 brick
= 49500/0.75=66000
therefore, 66000 bricks were used to pave the lane.
area of one brick = l×b
= 20×15
= 300cm^2
area of the lane = total no. of bricks used×area of one brick
=66000×300
area of the lane=19800000cm^2
19800000=l×b
19800000/breadth of the lane=length of the lane
19800000/500=lenght
39600cm OR 396m is the lenght of the lane
hope this answer helped you.
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if 1000 bricks cost Rs. 750
then 1 brick costs 750/1000=Rs. 0.75
if total bricks used cost Rs. 49500.
then no. of bricks used
= cost of total no. of bricks used/cost of 1 brick
= 49500/0.75=66000
therefore, 66000 bricks were used to pave the lane.
area of one brick = l×b
= 20×15
= 300cm^2
area of the lane = total no. of bricks used×area of one brick
=66000×300
area of the lane=19800000cm^2
19800000=l×b
19800000/breadth of the lane=length of the lane
19800000/500=lenght
39600cm OR 396m is the lenght of the lane
hope this answer helped you.
pls mark as brainliest
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