Question

A 5m wide path is constructed all along the outer edge of a rectangular plot, measuring 80m×40m. the area of the path will be​

Answer 1

Answer:

Length of inner rectangle =60m

Breadth of inner rectangle =30m

Thickness of lawn =5m

⇒ Length of outer rectangle =60+5+5=70m

Breadth of outer rectangle =30+5+5=40m

Area of lawn = Area of outer rectangle − Area of inner rectangle

=70×40−60×30

=2800−1800

=1000m²

Answer 2

Given,

• Length of inner triangle = 80 m

• Breadth of inner triangle = 40 m

• Thickness of the path = 5 m

• Length of outer triangle = 80+5+5 = 90 m

• Breadth of outer triangle = 40+5+5 = 50 m

We know the equation:

$\boxed{\bold{\sf{Area \ of \ Rectangle=Length\times Breadth}}}$

$\sf{\implies Area \ of \ outer \ Rectangle=90\times50=4500 \ m^2}$

$\sf{\implies Area \ of \ inner \ Rectangle=80\times40=3200 \ m^2}$

$\boxed{\bold{\sf{Area \ of \ Path=Area \ of \ outer \ Rectangle-Area \ of \ inner \ Rectangle}}}$

$\sf{\implies Area \ of \ Path=4500-3200}$

$\sf{\implies Area \ of \ Path=1300 \ m^2}$

$\boxed{\bold{\sf{\therefore Area \ of \ Path=1300 \ m^2}}}$