Question

A 5m60cm high vertical pole casts a shadow 3m20cm long. Find at the same
time​

Answer 1

Correct Question :-

• A 5m60cm high vertical pole casts a shadow 3m20cm long. Find at the same time (i) the length of the shadow cast by another pole 10m50cm high (ii) the height of a pole which casts a shadow 5m long.

Answer :-

Consider there is a direct proportion relation of pole height with pole shadow.

Consider there is a direct proportion relation of pole height with pole shadow.So we have 5m 60cm high verticle pole that casts a shadow of 3m 20cm long .

Consider there is a direct proportion relation of pole height with pole shadow.So we have 5m 60cm high verticle pole that casts a shadow of 3m 20cm long .hence,

Consider there is a direct proportion relation of pole height with pole shadow.So we have 5m 60cm high verticle pole that casts a shadow of 3m 20cm long .hence,(i) for the length of the shadow cast by another pole of 10 m 50cm high would be 'x' cm;

$\frac{560cm}{320cm} = \frac{1050}{x}$

$\frac{ \cancel{560}}{ \cancel{320}} = \frac{1050}{x}$

$\frac{1.75}{1} = \frac{1050}{x}$

$1.75x = 1050$

$x = \frac{ \cancel{1050}}{\cancel{1.75}}$

$x = 600cm.$

Therefore for a 10m 50cm pole we would get a shadow of 600cm or 6m length.

(ii) The height of a pole which casts a shadow of 5m long let it be 'y'

(ii) The height of a pole which casts a shadow of 5m long let it be 'y'similar relation holds here also, so we can apply it once more

$\frac{560cm}{320cm} = \frac{y}{500cm}$

$\frac{ \cancel{560}}{ \cancel{320}} = \frac{y}{500}$

$1.75 = \frac{y}{500}$

$1.75 \times 500 = y$

$y = 875.$

we get y = 875cm or 8m 75cm.

75cm.Thus, the height of a pole which casts a shadow of 5m long is 8m 75cm.