Question

A 5N weight is balanced on the top of a vertical wheel of radius 1 m. The torque, exerted by the weight, on the axis of rotation of the wheel is

5 Nm
6 Nm
1 Nm
Zero

Answer 1

Answer:

zero

please give me support

Answer 2

Torque exerted on the wheel is (d)zero newton.

Given:

Force exerted by the weight = 5 N

Radius of the wheel = 1 m

To find:

Torque exerted by the weight on the axis of the wheel

Explanation:

• Torque, is a term used in rotational mechanics for force exerted on  rotating body by virtue of which movement or displacement is produced by the body.
• Mathematically, torque is the cross product of the linear force and the distance between the axis of rotation and point of application of force.

           Torque τ = F × R

                         τ = F R sinθ

       where,

        τ (Tou) = torque

        F =  force

        R = radius ; and

        sinθ = angle made by the direction of application of force and radius R

Solution:

We have been given that the load or weight is kept on top off a vertical wheel and the force exerted by the mass = 5 N.

Here, we see that the angle made by the load with the axis of the wheel is 0°, since the load is kept on top of a vertical wheel. The force generated by the load is acted towards the ground.

Since, there is no angle made therefore, no torque could be produced by the wheel.

Mathematically,

τ =  F R sinθ

τ = (5) (1) sin(0°)

Hence,

τ = 0 N

Final answer:

Hence, the torque exerted by the weight on the axis of the wheel is 0 N.