Question

A=5x(square) +7x + 8 and B=4x(square) - 7x + 3,Find 2A-B

Answer 1

$Given \: A = 5x^{2} + 7x + 8 \: and$ $B=4x^{2}-7x+3$

$\red{ Value \:of \: 2A-B }$

$= 2( 5x^{2} + 7x + 8 ) - ( 4x^{2}-7x+3)$

$= 10x^{2} + 14x + 16 - 4x^{2} + 7x - 3$

$= ( 10-4)x^{2} + (14+7)x + 16 - 3$

$= 6x^{2} + 21x + 13$

Therefore.

$\red{ Value \:of \: 2A-B }$

$\green { = 6x^{2} + 21x + 13 }$

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