A 6.0-kg mass moves along the x-axis on the smooth surface. At t = 0 its position is
x = 0. Find: (i) its velocity vx in the final position, (ii) its acceleration ax in the final
position, (iii) power P used to shift the mass; in two cases:
(a) if the mass moves a distance of 3.0 meters under the influence of the force
Fx = (3.0 + 4.0x) [N],
(b) if the masses moves for 3.0 seconds under the influence of the force
Fx = (3.0 + 4.0t) [N].
Thank you in advance :)
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Answer:
60.000 ×3.0+40.0tyuNN
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