A 6.0 newton force is applied to a 4.5 kilogram block that is initially at rest on a frictionless, horizontal surface. If the block moves 12 meters in 3.0 seconds, what is the average power developed while moving the block?
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1
power is force times displacement
power = 6(12/3)
=6(4)
=24N
hope it helps you
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power = 6(12/3)
=6(4)
=24N
hope it helps you
please mark me as brainliest for answering first
Answered by
0
the answer is power is24
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