Question

A(6,-5),b(-2,-4),c(2,10) isosceles triangle

Answer 1

Answer:

yes it is an isoceles triangle

Step-by-step explanation:

Answer 2

Hi ,

Given points are A(6,-4),B(-2,-4)

and C(2,10)

****************************************

The distance between points

P(x1, y1) and Q(x2,y2) is

PQ = √(x2 - x1)² + ( y2 - y1)²

****************************************

i )Distance between A(6,-4) and B(-2,-4)

AB = √[-2-6 ]² + [ -4 - ( -4 )]²

= √ (-8)²+ 0

AB = 8

ii )Distance between B(-2,-4) and C(2,10)

BC= √[ 2 - (-2 )]² + [ 10 - (-4)]²

= √ 4² + 14²

= √ 16 + 196

BC = √212

iii ) distance between C(2,10) and A(6,-4)

CA = √(6-2)² + ( -4 -10 )²

= √ 4² + 14²

= √ 16 + 196

= √212

BC = CA = √212

Therefore ,

In ∆ABC , BC = CA

ABC is an isosceles triangle.

I hope this helps you.

: )