A 6.8kg block is sliding down horizontal, frictionless surface at a constant speed of 6.0m per second. The kinetic energy of the block is approximately
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Answer:
122.4J
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Explanation:
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Given - Mass and velocity
Find - Kinetic energy
Solution - Kinetic energy is calculated by the formula - 1/2*m*v². Keep the values in formula to find the kinetic energy.
K.E. =
Taking square and performing division
K.E. =
Performing multiplication
K.E. = 122.4 Joules
Hence, kinetic energy of the block is approximately 122.4 Joules.
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