Question

A 6.8kg block is sliding down horizontal, frictionless surface at a constant speed of 6.0m per second. The kinetic energy of the block is approximately

Answer 1

Answer:

122.4J

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Explanation:

Answer 2

Given - Mass and velocity

Find - Kinetic energy

Solution - Kinetic energy is calculated by the formula - 1/2*m*v². Keep the values in formula to find the kinetic energy.

K.E. = $\frac{1}{2} \times 6.8 \times {6}^{2}$

Taking square and performing division

K.E. = $3.4 \times 36$

Performing multiplication

K.E. = 122.4 Joules

Hence, kinetic energy of the block is approximately 122.4 Joules.