Question

A 6 cm B 6 cm EL •C 16 cm
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Answer 1

Answer:

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Step-by-step explanation:

Answer is no .

because as we know that according to theorem when we add to smaller sides of triangle then it must be greater than 3rd side .

but here ,

6 + 6 = 12 ( isn't = 16 )

hence , we can't construct a triangle .

hope it helps .

Answer 2

Answer:

Diagonals of rhombus are cut each other at 90

Diagonals of rhombus are cut each other at 90 o

Diagonals of rhombus are cut each other at 90 o .

Diagonals of rhombus are cut each other at 90 o .Since d

Diagonals of rhombus are cut each other at 90 o .Since d 1

Diagonals of rhombus are cut each other at 90 o .Since d 1

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =(

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 )

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +(

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 )

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8 2 +6

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8 2 +6 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8 2 +6 2

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8 2 +6 2 ⇒ a=

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8 2 +6 2 ⇒ a= 100

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8 2 +6 2 ⇒ a= 100

Diagonals of rhombus are cut each other at 90 o .Since d 1 =16and d 2 =12Therefore, by Pythagoras theorem a 2 =( 2d 1 ) 2 +( 2d 2 ) 2 ⇒ a 2 =8 2 +6 2 ⇒ a= 100 =10

I hope this answer help you

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