Question

A 6 cm object is placed perpendicular to the principal axis of a concave ens of focal length 15 cm. The distance of the object from the lens is 10 cm. Find the position, size and nature of the image formed, using the lens formula.

Answer 1

Answer:

Given : u=−10 cm f=−5 cm h

o

=6 cm

Using lens formula :

v

1

−

u

1

=

f

1

∴

v

1

−

(−10)

1

=

−5

1

⟹v=−

3

10

=−3.33 cm (- sign shows that image is virtual)

Also m=

h

o

h

i

=

u

v

∴

6

h

i

=

−10

3

−10

⟹h

i

=+2 cm (+ sign shows that image is erect)

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Explanation:

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