Question

A 6 cm tall object is placed on the principal axis of a convex lens of focal length 25cm

Answer 1

I don't know do by yourself

Answer 2

$\mathcal{Correct\: Question\:-}$

A 6 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 25 cm. The distance of the object from the lens is 40 cm.

Then, determine

$\textit{(i)\: the\: position}$

$\textit{(ii)\: and\: the\: size\:of\:the\: image\: formed}$

⠀⠀⠀⠀⠀───────•••───────

$\textbf{GIVEN,}$

• ${ \tt{height \:of \:the \:object,}}$ $h_{o}$ = 6cm

• ${ \tt{Focal \:length\:of \:lens,}}$ f = 25 cm

• ${ \tt{Distance\: of \:object,}}$ u = - 40 cm

${ \tt{(i) \:Using\:lens\: formula}}$, ⠀$\bf\dfrac{1}{f}$ = $\bf\dfrac{1}{v}$ - $\bf\dfrac{1}{u}$

⠀⠀⠀⠀$\implies$ $\bf\dfrac{1}{v}$ = $\bf\dfrac{1}{f}$ + $\bf\dfrac{1}{u}$

⠀⠀⠀⠀$\implies$ $\bf\dfrac{1}{25}$ + $\bf\dfrac{1}{(-40)}$ = $\bf\dfrac{8-5}{200}$ = $\bf\dfrac{3}{200}$

⠀⠀⠀⠀⠀$\mathcal{v}$ = $\bf\dfrac{200}{3}$ = $\small{\underline{\mathcal{\green{66.67 \:cm }}}}$

⠀⠀⠀⠀

${ \tt{(ii)}}$ $\therefore$ ${ \tt{Magnification,}}$ m = $h_{i}$ / $h_{o}$ = $\bf\dfrac{v}{u}$

⠀$h_{i}$ = $\frac{v}{u}$ × $h_{o}$ = $\bf\dfrac{200}{3×(-40)}$× 6 = $\small{\underline{\mathcal{\orange{- 10\: cm }}}}$

$\large\bf{\color{#880E4F}⠀⠀⠀⠀◈━━ཞ⚆ƈӄֆ╬ꪖƦ━━ ◈}$