A 6 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 16 cm. The distance of the object from the lens is 9 cm. Using the lens formula
1) Find the position
2) size
3) Nature of the image formed.
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Answer:
height of object = 6cm
focal length of convex lens, f = +15cm
object distance from the lens, u = -10cm
from lens maker formula,
1/v - 1/u = 1/f
1/v - 1/-10 = 1/15
or, 1/v = 1/15 - 1/10
or, 1/v = 2/30 - 3/30 = -1/30
or, v = -30cm
hence, position of image is 30cm aways from the lens.
magnification, m = v/u
or, height of image/height of object = v/u
or, height of image/6cm = (-30cm)/(-10cm)
or, height of image = 18cm
hence, height of image is 18cm ( larger than object )
so, position of image => 30cm
size of image => 18cm
nature of image => real and enlarged
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