Question

A 6 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 15cm .the distance of the object from the lens is 10cm. find the position,size and nature of the image formed, using the lens formula

Answer 1

Here's the answer to your question.......

Hope it will help you.

Answer 2

The image will be formed at a distance of 30 cm from the lens and it is virtual and erect having size of image is 18 cm.

Explanation:

It is given that,

Height of the object, h = 6 cm

Object distance, u = -10 cm

Focal length of the convex lens, f = +15 cm (for convex mirror it is positive)

(a) Let the object is placed at a distance of v from the lens. It can be calculated using mirror's formula as :

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{(u)}$  

$\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-10)}$  

v = -30 cm

So, the image will be formed at a distance of 30 cm from the lens.  

(b) Magnification,

$m=\dfrac{v}{u}=\dfrac{h'}{h}$

h' is the size of image

$h'=h\dfrac{v}{u}$

$h'=6\times \dfrac{-30}{-10}$

h' = 18 cm

So, the size of image is 18 cm and it is virtual and erect.  

Hence, this is the required solution.

Learn more,

Mirror's formula

https://brainly.in/question/8281335