Question

a=6,d=3 then,find s10

Answer 1

s10= n/2{2a+{n-1}d}
put all values:-
 10/2{2×6+{10-1}3}
5{12+9×3}
5{12+27}
5{39}
=195 ans.

Answer 2

Heya !!

Here is your answer.

Given, a = 6 , d = 3 , S10 = ?

Sn = n/2 [ 2a + (n-1)d ]

S10 = 10/2 [ 2*6 + (10-1)3 ]

= 5 ( 12 + 27 )

= 5*39

= 195

Hope it helps.