Question

A 6 kg ball strikes a vertical wall with a velocity of 34 m/s and rebound with a velocity of 26 m/s the impulse is

Answer 1

Answer:

Explanation:

impulse is equal to change in momentum

=m(v-u)

=6*8

=48kg m/s

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Impulse=48\:N-s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a 6 kg ball that strikes a vertical wall with velocity of 34 m/s and then rebounds with another velocity of 26 m/s.

• We have to find Impusle.

$\green{\underline \bold{Given : }} \\ \\ :\implies \text{Mass \: of \: ball = 6 \: kg} \\ \\ :\implies \text{Initial \:velocity(u) = 34 \: m/s} \\ \\ :\implies \text{Final \: velocity (v)= 26 \: m/s} \\ \\ \green{\underline \bold{To \: Find : }} \\ \\ :\implies Impulse = ?$

• According to given question :

$\bold{According\:to\:Impulse\:formula:}\\\\:\implies I= F\times T\\\\\bold{I= impulse}\\\bold{F= force}\\\bold{T= time}\\\\ :\implies I= F\times T-----(1)\\\\\bold{Using\:formula\: of \: force:}\\\\ :\implies F=Ma\\\\ :\implies F=M(\frac{v - u}{T}) -----(2)\\\\\bold{Putting\:value\:of\:F\:in\:(1)}\\\\ :\implies I=M\times\frac{(v - u)}{T}\times T\\\\ :\implies I=M\times(v - u)\\\\ :\implies I=6\times(34 - 26)\\\\ :\implies I=6\times8\\\\\green{:\implies I= 48\:N-s}$