A 6 kg box is being pushed horizontally on a surface by a 10 N force for 6 m. Given that the box has initial speed of 4 m/s, and the floor has friction force of 2 N. What is the speed of the box at the end of the 6 m?
Answers
Answered by
2
Answer:
Work done by all the forces= change in kinetic energy
Work done by applied force= 10*6 =60Nm
Work done by force of friction= -2*6
= -12Nm
Total work done by all forces in box= 60-12 = 48Nm = change in kinetic energy
48= 0.5*m*v^2 - 0.5*m*u^2
16 = v^2 -16
v = 4√2 m/s
Explanation:
Similar questions