Question

.A 6 kg object is subject to three forces F1 = 20i + 30j N , F2 = 8i - 50j N and F3 = 2i + 2j N find accleration

Answer 1

Given:

A 6kg object is subjected to forces

F$_1=$ 20î+30ĵ N

F$_2=$ 8î-50ĵ N

F$_3=$ 2î+2ĵ N

To Find:

Acceleration of the object.

Solution:

In this problem, we know the mass of the object $m=6kg$.

From Newton's laws of motion, we also know the relation between force and acceleration of a body, $F=ma$.

So, if we find the total force F on the body, we can know its acceleration.

F$=$ F$_1$+F$_2$+F$_3$

 $=$ 20î+30ĵ+8î-50ĵ+2î+2ĵ

 $=$ 30î-18ĵ N

Acceleration of the object,

   $a=$ F$/m$

⇒ $a=$ 5î-3ĵ $m/s^2$

Hence, the acceleration of the object is equal to 5î-3ĵ $m/s^2$.

Answer 2

Explanation:

Given:

mass = 6k

F1 = 20i+30j N

F2 = 8i-50j N

F3 = 2i+2j N

acceleration of the object (a) = F1 + F2 + F3/mass

a=20i + 30j + 8i - 50j + 2i + 2j/6

=30i - 18j/6

=5i - 3j meter/second square(m/s^2)

The project code is #SPJ2