Question

A 6-meter long ladder is leaning against a wall. If the top of the ladder makes an angles 45 degrees with the wall, how far is the foot of the ladder from the wall?

Answer 1

Answer:

Step-by-step explanation:

It is given that

Length of ladder =6 m

Ladder reaches the wall to a height of 4.8 m

Consider AB as the ladder and AC as the height of the wall

AB=6 m and AC=4.8 m

Distance between the foot of ladder and wall is BC

Using Pythagoras theorem,

AB2=AC2+BC2

Substituting the values

62=4.82+BC2

By further calculation

BC2=62−4.82

BC2=36−23.04=12.96

So we get

BC=√12.96=3.6 m

Hence, the distance between the wall and the foot of the ladder is 3.6 m.