A 6 N weight is hung on a spring that is extended by 0.2 m, what is the spring constant (k) of the spring?
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Dear Student,
● Answer -
Spring constant of the spring is 30 N/m
● Explaination -
# Given -
F = 6 N
x = 0.2 m
# Solution -
Magnitude of restoring force is related to extension as -
F = kx
Substitute values,
6 = k × 0.2
k = 6 / 0.2
k = 30 N/m
Hence, spring constant of the spring is 30 N/m.
Thanks dear. Hope this helps you...
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