Question

A 6 ohm resistance wire is doubled by folding. what is the new resistanne?

Answer 1

Given :
R=6ohms
R=ρl/A-------------(1)
Wire is doubled so, Area =A=2A
length=l=l/2
New Reistance will be:
Rnew=ρ(l/2)/2A
Rnew=ρl/4A
Rnew=R/4-----(from equ 1)
Rnew=6/4=1.5 ohms
Hence new Reistance of wire is 1.5ohms.

Answer 2

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