Physics, asked by sruthilakshmik87, 11 months ago

A 6 ohm resistance wire is doubled on itself .calculate the new resistance of the wire

Answers

Answered by KILLERABHI9

Answer:

Resistance=ρL/A Here, Resistance=6ohm Therefore,6=ρL/A In second case, Resistance,R'=ρL'/A' As the wire is doubled so L'=L/2, A'=2A So new resistance,R'=ρL/4A=(1/4)ρL/A But ρL/A=6 So, R'=6/4=1.5Ω

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Answered by alexjoby21

Answer:

It is given that the wire is doubled on itself. Therefore. area increases . If area increase , resistance decrease , therefore it so should be connected in parallel to get a low resistance value.

Explanation:

Rp =R1*R2/R1+R2

Rp = 6*6/6+6

= 36/12

= 3ohm

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