a 6 ohm resistance wire is doubled up by folding calculate the new resistance of the wire
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Hello!
Given ---›
R = 6ohm
Since wire is doubled so,
Area (A) = 2A
Length (l) = l/2
Using formula ===>
R = pl/A.........(1)
R' = pl/2*2A
R' = pl/4A........(2)
From (1) and (2)
R' = R/4
R' = 6/4
R' = 1.5 ohm
Thanks!
Given ---›
R = 6ohm
Since wire is doubled so,
Area (A) = 2A
Length (l) = l/2
Using formula ===>
R = pl/A.........(1)
R' = pl/2*2A
R' = pl/4A........(2)
From (1) and (2)
R' = R/4
R' = 6/4
R' = 1.5 ohm
Thanks!
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