Question

A
6. Sahil earns 10% more than Satish and
Satish earns 20% more than Swati. If Swati
earns *17,500 less than Sahil, find the
earnings of each.​

Answer 1

Step-by-step explanation:

Given:-

• Sahil earns 10% more than Satish.

• Satish earns 20% more than Swati.

• Swati earns Rs.17500 less than Sahil.

To Find:-

• The earnings of each of them.

Solution:-

$\rm Let \: the \: earning\: of \: Swathi \: be\: Rs. x$

$\rm Earnings\: of\: Satish = x + 20\% \:of \: x$

$\rm = x + \dfrac{20}{100} \times x$

$\rm = \dfrac{100x + 20x}{100}$

$\rm = \dfrac{120x}{100} = \dfrac{12x}{10}$

$\rm Earnings \:of \: Satish = \dfrac{12x}{10}$

$\rm Earnings \: of \: Sahil = \dfrac{12x}{10} + 10\% \: of \: \dfrac{12x}{10}$

$\rm = \dfrac{12x}{10} + \dfrac{12x}{100}$

$\rm = \dfrac{120x + 12x}{100}$

$\rm = \dfrac{132x}{100}$

$\rm Earnings \: of \: Sahil = \dfrac{132x}{100}$

Given, Swati earns Rs.17500 less than Sahil.

$\rm \implies \dfrac{132x}{100} - x = 17500$

$\rm \implies \dfrac{132x-100x}{100} = 17500$

$\rm \implies \dfrac{32x}{100}= 17500$

$\rm \implies x = 17500\times \dfrac{100}{32}$

$\rm \implies x = 54687.5$

$\rm Earnings \: of\: Swathi = x = 54687.5$

$\rm Earnings\: of \: Satish :-$

$\rm = \dfrac{12x}{10}$

$\rm = \dfrac{12 \times 54687.5}{10}$

$\rm = 65625$

$\rm Earnings \: of Sahil \: :-$

$\rm = \dfrac{132x}{100}$

$\rm = \dfrac{132 \times 54687.5}{100}$

$\rm = 72187.5$

Therefore:-

Earnings of Swathi = Rs. 54687.5

Earnings of Satish = Rs. 65625

Earnings of Sahil = Rs. 72187.5

Answer 2

Step-by-step explanation:

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