Question

A 6 volt battery is connected with a series combination of 1 and 2 ohm resistors the power developed is

Answer 1

Potential difference = 6 V

Resistance of resistors = 1 Ω and 2 Ω

Power used through resistors of 2 Ω =?

Since, resistors are connected in series, thus, total effective resitance,

R

=

1

Ω

+

2

Ω

=

3

Ω

We know;

I

=

V

R

=

6

V

÷

3

Ω

=

2

A

Since current remains same when resistors are connected in series, hence current through resistor of 2 Ω = 2 A

Thus, power

(

P

)

=

I

2

×

R

=

(

2

A

)

2

×

2

Ω

=

8

W

A 4 V battery in parallel with 12 Ω and 2 Ω resistors.