A 60.0-kg person walks from the ground to the roof of a 74.8-m tall building. How much gravitational potential energy does she have at the top of the building?
Answers
Answered by
122
Given:
m=60.0 kg
g=9.8m/s² (assuming they haven't built any extraterrestrial buildings, lol)
h=74.8 m
Gravitational Potential Energy = mg∆h
= 60.0×9.8×(74.8-0)
= 43,982.4 J
m=60.0 kg
g=9.8m/s² (assuming they haven't built any extraterrestrial buildings, lol)
h=74.8 m
Gravitational Potential Energy = mg∆h
= 60.0×9.8×(74.8-0)
= 43,982.4 J
Answered by
31
This is our formula...
Gravitational Potential Energy = mgh or ( GPE = mgh )
mg= 60.0 kg
h= 74.8
****************
mg= 60.0 kg <<< We need to transform this to force (N) because we are looking for force, and the SI Unit for force is "N"
so were going to multiply 60.0 to 9.81
60.0 * 9.81 = 588.6
so now, it will be...
> mg= 588.6 N
> h= 74.8
GPE = (588.6) (74.8) = 44027.28
FINAL ANSWER: GPE = 44027.28 J
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