Question

A 60.00 g sample of tetraethyl-lead, a gasoline additive, is found to contain 38.43 g lead, 17.83 g carbon, 3.74g Hydrogen. Find the Empirical Formula

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Answer 1

in a 60g sample of tetraethyl-lead, a gasoline is addictive , is found contain 38.43g lead , 17.83g carbon and 3.74g hydrogen.

percentage mass of Pb = 38.43/60 × 100

≈ 64.05 %

percentage mass of C = 17.83/60 × 100

≈ 29.71%

percentage mass of H = 3.74/60 × 100

≈ 6.23%

now, finding percentage - atomic mass ratio

Pb => 64.05/207 = 0.3094

C => 29.71/12 = 2.475

H => 6.23/1 = 6.23

finding simple ratio of above terms

Pb : C : H = 1 : 8 : 20

hence, empirical formula is PbC6H20 or, $PbC_8H_{20}$

Answer 2

Answer:

Explanation:60.00 g sample of tetraethyl lead, a gasoline additive, is found to contain 38.43 g lead, 17.83 g carbon, and 3.74 g hydrogen. Find its empirical formula *