Question

A=60 , B=30
find, sin(A-B) = sinA cosB-cosA SinaB​

Answer 1

Answer:

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\sin(60 + 30) = \sin(30) \times \cos(60) + \cos(30) \times \sin(60) \\ \sin(90) = 1 \div 2 \times 1 \div 2 + \sqrt{3} \div 2 \times \sqrt{3} \div 2 \\ 1 = 1 \div 4 + 3 \div 4 \\ 1 = 1 \\ \\ also \: \cos( 90) = \cos(30) \times \ \cos(60) - \sin(30) \times \sin(60) \\ \cos(90) = \sqrt{3} \div 2 \times 1 \div 2 - 1 \div 2 \times \sqrt{3} \div 2 \\ 0 = 0

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Answer 2

Step-by-step explanation:

sin(30)=sin60cos30-cos60sin30

=√3/2.1/2-1/2-1/2

=√3/2.1/2

=√3/2=60 degree