Question

A 60 g man stands on an elevator floor.The elevator is going up with constant acceleration of 1.96 m/s².Percentage change in the apparent weigth of the person is options are
1.10
2.15
3.20
4.25

Answer 1

ma=r-mg R=mg+ma=m (g+a)=(60÷1000)×(9.8+1.96)=.7056.kg Primary weight .6kg Last weight .7056kg excess of weight=.1056kg Percent (.1056÷.7056)×100=14.96%=15%