A 60 kg body is pushed horizontally with just enough force to start it moving across a floor and the same force continues to act afterwards. the coefficient of static friction and sliding friction are 0.5 and 0.4 respectively. the acceleration of the body is
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As we know that static friction = coefficient of static friction * normal reaction of the body
that is friction = (u)N
also N=(m)(g) =60* 10 = 600 N ( By just taking g= 10 m/s^2
static friction = 0.5 * 600 = 300 N
when the external force will be applied on body .it will be start moving so in this case kinetic friction= 0.4 * 600 = 240 N
so the net force will be difference of both type of friction = 300- 240 = 60 N
we know that
F= ma so
a=F/m
so by butting values 60/60 =1 m/s^2 (acceleration).
As we know that static friction = coefficient of static friction * normal reaction of the body
that is friction = (u)N
also N=(m)(g) =60* 10 = 600 N ( By just taking g= 10 m/s^2
static friction = 0.5 * 600 = 300 N
when the external force will be applied on body .it will be start moving so in this case kinetic friction= 0.4 * 600 = 240 N
so the net force will be difference of both type of friction = 300- 240 = 60 N
we know that
F= ma so
a=F/m
so by butting values 60/60 =1 m/s^2 (acceleration).
Answered by
1
Answer:
Explanation: acceleration = coefficient of friction * gravity
body just begins to slide so there is no static friction so there is limiting friction so acceleration = 0.4*9.8
= 3.92 meters / second ^ 2
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