Physics, asked by S171076, 1 month ago

A 60 kg car model collides with another model of 90 kg. The lighter model moves towards the heavier model with a velocity of 50 cm/s. The heavier model moves with 70 cm/s in the opposite direction. After the collision, the 90 kg model moves with 20 cm/s in the opposite direction. Find the velocity of the 60 kg model after the collision.

Answers

Answered by harisreeps
1

Answer:

A 60 kg car model collides with another model of 90 kg. The lighter model moves towards the heavier model with a velocity of 50 cm/s. The heavier model moves with 70 cm/s in the opposite direction. After the collision, the 90 kg model moves with 20 cm/s in the opposite direction. The velocity of the 60 kg model after the collision is 25cm/s

Explanation:

The momentum is conserved when two different objects collide with each other, that is total momentum before collision should be equal to the total momentum after the collision.

From the question, two cars are moving in the opposite direction before the collision after the collision heavier car moves in the opposite direction and the lighter moves along the same direction as shown in the figure.

The mass of the lighter car m_{1} =60kg

and that of the heavier car is m_{2}=90kg

the velocity of the lighter car before the collision is  V_{1}=50cm/s

the velocity of the heavier car before the collision is V_{2}=70cm/s

the velocity of the heavier car after the collision is U_{2}=20cm/s

let the velocity of the lighter car be U_{1} which we need to find

From momentum conservation,

m_{1} V_{1} +m_{2} (-V_{2} )=m_{1} U_{1} +m_{2} U_{2} (negative sign is due to opposite direction)

substituting the values we get,

60*50-90*70=90*20+60U_{1} \\U_{1}=15/0.6=25cm/s

 

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