Question

A 60 kg girl wearing high heels shoes balance on a single heel. The heel is circular with a diameter of 15 cm. Find the pressure exerted by the heel on the horizontal floor

Answer 1

Answer:

33200pa

Explanation:

pressure=force/volume

force exerted by heels=60kg×9.8m/s^2

=588N

area of heels=π *r^2

=3.14*15/2^2

almost equal to 177cm^2

pressure=558/177

=3.32N/cm^2 or33200N/m^2

Answer 2

Answer:-

★ Given:-

Radius of the heel, r = $\dfrac{ d }{ 2 }$ = 0.004m

Mass of the lady, m = 60 kg

Diameter of the heel, d = 0.8 cm = 0.008 m

Area of the heel, A = πr² = π (0.004)²= $5.024\times {10}^{-5}$m²

★ Force on the floor due to the heel:-

F = mg = 60 × 9.8 = 588 N

★ Pressure exerted by the heel on the floor:-

P = $\frac{ F }{ A }$ = $\frac{ 588 }{ 5.024 \times 10^{ -5 }}$

P = $1.17 \times 10^{ 7 }$Nm-²

Hence, the pressure exerted by the wheel on the horizontal floor is $1.17 \times 10^{ 7 }$Nm-²