Question

A 60 kg man stands on elevator floor the elevator is going up with constant acceleration of 1.96 metres per second square percentage change in the Apparent weight of the person is

Answer 1

Answer:

19.6%

Explanation:

The apparent weight of the man in standing elevator, W=mg,

W=60(10)=600N

Now if the elevator is accelerating upwards then the apparent weight of the man, W'=m(g+a)

W'=m(10+1.96)

W'=60(11.96)=717.6

Relative change in apparent weight=(W'-W)÷W

(717.6-600)÷600=0.196

Percentage relative change=

Relative change×100

0.196×100=19.6