A 60 kg painter stands on a 15 kg platform. a rope attached to the platform and passing over an overhead pulley allows the painter to raise himself along with the platform.
To get started,he pulls the rope down with a force of 400N. find the acceleration of the platform as well as that of painter
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f = ma , 400=75 ×a, a=400/75 , a=5.3m/sec^2
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Answer:
Explanation:The FBD of the painter and the platform can be drawn as shown in the solution..Tension in the string is equal to the force by which he pulls the rope
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