A 60 litre solution of alcohol and water contains 20 litres of alcohol. How much alcohol must be added to produce of resolution of 50 litre alcohol?
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Let us assume we add "a" litre of alcohol to make the mixture 50%
so new qty. of alcohol = (20 + a) litre
and new total quantity of mixture will be = (60 + a) litre
so New % of alcohol in the mixture would be = Qty. of Alcohol in the mixture / Tot. quantity
50% = (20 + a) / (60 + a) ; 50% is same as 50 / 100 or 0.5 or ½
0.50*(60 + a) = (20 + a)
½*60 + ½ (a) = 20 + a
30 + ½ (a) = 20 + a
30 - 20 = a - ½ (a)
10 = ½ (a)
=>a = 20 litre
so we have to add 20 litre of alcohol, , so that total alcohol would become = 40 litre
and total qty of mixture would be 60 + 20 = 80 litre, which means mixture will have 50% alcohol as 40 litre is 50% of 80 litre.
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