A 60 litre tank was full of petrol. Peter used 30% of it and poured the rest into a
50 litre tank.
(1) What percent of 50 litre tank was filled with petrol?
(ii) If Peter used 2.8 litres of petrol daily, what percent of petrol in the 50 litre tank
would be used in 10 days?
Answers
Answer:
1) 30% of 60L = 18
remaining = 42 L
in 50L tank , 42/50×100 = 84%
2) petrol used daily = 2.8L
10 days =2.8×10
=28L
percentage = 28/42×100
=66.6 %
If a 60 litre tank was full of petrol, and Peter used 30% of it and poured the rest into a 50 litre tank, then
Percent of 50 litre tank filled with petrol = 84%
Percent of petrol in the 50 litre tank used in 10 days, if Peter used 2.8 litres of petrol daily = 66.67%
Given:
i) A 60 litre tank was full of petrol
ii) Peter used 30% of it and poured the rest into a 50 litre tank.
To find:
(1) Percent of 50 litre tank filled with petrol
(ii) Percent of petrol in the 50 litre tank used in 10 days, if Peter used 2.8 litres of petrol daily.
Solution:
(i)
Amount of tank filled initially = 60 litre
Amount of petrol used by Peter = 30% = (30/100)*60
= 18 litres.
Therefore,
the amount of petrol poured into 50 litre tank = 60 - 18
= 42 litres
Therefore,
Percent of 50 litre tank filled with petrol = (42/50)*100
= 84%
(ii)
Peter used 2.8 litres of petrol daily, it implies that in 10 days he will use up: (2.8) * 10 = 28 litres
The amount of petrol used up by Peter in 10 days = (28/42)*100
= 66.67%
Hence,
If a 60 litre tank was full of petrol, and Peter used 30% of it and poured the rest into a 50 litre tank, then
Percent of 50 litre tank filled with petrol = 84%
Percent of petrol in the 50 litre tank used in 10 days, if Peter used 2.8 litres of petrol daily = 66.67%
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