Question

A 60 m rope is laid along the boundary of a rectangular field. If tha length of the field is twice that of breadth, find the dimensions of the field. Solutions

Answer 1

Answer:

Step-by-step explanation:

Let the breadth be x

So length is 2x

Perimeter is given

60

By the problem

60 = 2(l+b)

60 = 2(2x + x)

60 = 4x + 2x

60 = 6x

6x = 60

x = 60/6

x = 10

Breadth is 10 m

Length will be 2 x 10 which is 20 m

Answer 2

Answer:

10*20 m

Step-by-step explanation:

We can take b as x and a as 2x

Perimeter of rectangle=60

= 2(x+2x)=60

=2*3x=60

=3x=60/2

=3x=30

=x=30/3

=x=10

So x=10

2x=10*2=20

Therefore the dimension is 10*20m