A 60 W bulb is connected to 230V mains supply. calculate the current through the bulb
Answers
hey mate,,,,,, here is ur answer
answr
answrsearch
answrsearchWhat would you like to ask?
answrsearchWhat would you like to ask?PHYSICS
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed is
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShare
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy later
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWER
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWERA 60 Watt 220V bulb means that it will consume 60 Watts when the voltage across it is 220V.
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWERA 60 Watt 220V bulb means that it will consume 60 Watts when the voltage across it is 220V.In such a case the current flowing through it will be given byI=W/V=60/220 Amperes.
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWERA 60 Watt 220V bulb means that it will consume 60 Watts when the voltage across it is 220V.In such a case the current flowing through it will be given byI=W/V=60/220 Amperes.And the resistance of the filament will be W/I 2
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWERA 60 Watt 220V bulb means that it will consume 60 Watts when the voltage across it is 220V.In such a case the current flowing through it will be given byI=W/V=60/220 Amperes.And the resistance of the filament will be W/I 2 =60×( 602) 2
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWERA 60 Watt 220V bulb means that it will consume 60 Watts when the voltage across it is 220V.In such a case the current flowing through it will be given byI=W/V=60/220 Amperes.And the resistance of the filament will be W/I 2 =60×( 602) 2 =806.67ohms
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWERA 60 Watt 220V bulb means that it will consume 60 Watts when the voltage across it is 220V.In such a case the current flowing through it will be given byI=W/V=60/220 Amperes.And the resistance of the filament will be W/I 2 =60×( 602) 2 =806.67ohmsNow when you just apply 110 volts across it instead of 220V. In this case the current flowing through the bulb will be given by,
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWERA 60 Watt 220V bulb means that it will consume 60 Watts when the voltage across it is 220V.In such a case the current flowing through it will be given byI=W/V=60/220 Amperes.And the resistance of the filament will be W/I 2 =60×( 602) 2 =806.67ohmsNow when you just apply 110 volts across it instead of 220V. In this case the current flowing through the bulb will be given by,V/R=110/806.67=0.136 Ampere
answrsearchWhat would you like to ask?PHYSICSA bulb rated 60W, 220V is connected across 110V mains line. The power consumed isShareStudy laterANSWERA 60 Watt 220V bulb means that it will consume 60 Watts when the voltage across it is 220V.In such a case the current flowing through it will be given byI=W/V=60/220 Amperes.And the resistance of the filament will be W/I 2 =60×( 602) 2 =806.67ohmsNow when you just apply 110 volts across it instead of 220V. In this case the current flowing through the bulb will be given by,V/R=110/806.67=0.136 AmpereAnd the power would beV×I=110×0.136=14.96≈15watts.