A 60 W bulb is switched ON for 6 hours on
alternate days in a month of 30 days. The energy
consumed in a month is :
(a) 19,440 kJ
(b) 1,296 kJ
(C) 8,100 kJ
(d) 2,560 kJ
Answers
Answer:
power in kilo watt =60/1000
=0.06kilo watt
time = 6 h
energy consumed by the bulb per day = p×t
=0.06×6
=0.36 units
Explanation:
Please mark it as a brainliest answer
Answer:
a) 19,440 kJ
Explanation:
Power consumed by bulb = 60 W = 0.06 KW
Time for one day = 6 hours
Total Days = 15
Because bulb is switched ON , on alternate days of month of 30 days.
Energy consumed in one day
Energy = Power × Time
= 0.06 × 6
= 3.6 KW-h
Energy consumed in 15 days
= 3.6 × 15
= 5.4 KW-h
We know 1 KW-h = 3.6 × 10^6
Therefore,
Total energy consumed = 5.4 × 3.6 × 10^6
= 19,440,000 J
= 19,440 KJ
Hope, it helped you.