Question

A 60 W light bulb has a resistance of 880 Ω
Calculate the CURRENT.
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Answer 1

$\bf{ \underline{Given:- }}$

$\sf{• \:  Power \:  (P) = 60 \:  w}$

$\sf{•  \: Resistance \:  (R) = 880  \: Ω}$

$\bf{ \underline{To \:  Find :- }}$

$\sf• \:  The  \: Current \:  (I).$

$\huge\bf{ \underline{ Solution :- }}$

$\sf We  \: know  \: that,$

$\bf \red {\bigstar{ \: P = I^{2} R}}$

$\rightarrow \sf 60 = I^{2}  \times 880$

$\rightarrow \sf  \frac{60}{880} = I^{2}$

$\rightarrow \sf  I^{2}   = 0.0681$

$\rightarrow \sf  I   =  \sqrt{0.0681}$

$\rightarrow \sf  I   =  0.261 \:  \: (approx.)$

$\bf The \: value \\:  of \:  I  \:  is \:  0.261 \:  Amps. \:  \: (approx.)$

Answer 2

answer 0.261 Amps.

hope it help u