a 60 watt lamp operates at 50% efficiency how much energy is dissipated in 10 seconds
Answers
Answer:
As some other answerers have pointed out, the Ampere is a measure of electrical current, not power. It's better to say that resistors (like light bulbs) draw current (measured in amperes), but consume power (measured in watts). So a 60-watt light bulb consumes 60 watts. In the US, the current through the bulb is driven by a 120-volt household supply. To find the current we need to know the resistance of the bulb. We can rearrange the power formula PR=V2 , where P is the power in watts, R is the resistance in ohms, and V is the voltage, in the form R=V2/P . So the light bulb has an effective resistance of 14400/60 = 240 ohms. Plugging that resistance into the Ohm's law equation I=V/R , where I is the current in amperes, we get 60/240 ohms = 0.25 amperes, or 250 milliamps. A quarter of an ampere. So if your outlet is limited to 15 amps, you could run 60 60-watt bulbs before you blow the breaker.
As some other answerers have pointed out, the Ampere is a measure of electrical current, not power. It's better to say that resistors (like light bulbs) draw current (measured in amperes), but consume power (measured in watts). So a 60-watt light bulb consumes 60 watts. In the US, the current through the bulb is driven by a 120-volt household supply. To find the current we need to know the resistance of the bulb. We can rearrange the power formula PR=V2 , where P is the power in watts, R is the resistance in ohms, and V is the voltage, in the form R=V2/P . So the light bulb has an effective resistance of 14400/60 = 240 ohms. Plugging that resistance into the Ohm's law equation I=V/R , where I is the current in amperes, we get 60/240 ohms = 0.25 amperes, or 250 milliamps. A quarter of an ampere. So if your outlet is limited to 15 amps, you could run 60 60-watt bulbs before you blow the breaker.In countries that use 240-volt household supply, a 60-watt bulb is designed with a much higher resistance (960 ohms), but draws the same current and consumes the same power.
As some other answerers have pointed out, the Ampere is a measure of electrical current, not power. It's better to say that resistors (like light bulbs) draw current (measured in amperes), but consume power (measured in watts). So a 60-watt light bulb consumes 60 watts. In the US, the current through the bulb is driven by a 120-volt household supply. To find the current we need to know the resistance of the bulb. We can rearrange the power formula PR=V2 , where P is the power in watts, R is the resistance in ohms, and V is the voltage, in the form R=V2/P . So the light bulb has an effective resistance of 14400/60 = 240 ohms. Plugging that resistance into the Ohm's law equation I=V/R , where I is the current in amperes, we get 60/240 ohms = 0.25 amperes, or 250 milliamps. A quarter of an ampere. So if your outlet is limited to 15 amps, you could run 60 60-watt bulbs before you blow the breaker.In countries that use 240-volt household supply, a 60-watt bulb is designed with a much higher resistance (960 ohms), but draws the same current and consumes the same power.Note that the “in one second” and “in one hour" mentioned in the question are unnecessary because current (as amperes, coulombs per second) and power (as watts, joules per second) already describe rates. To find the energy consumed by the bulb over the course of a year, we need to multiply the power by time. In one year, a continuously-burning 60-watt bulb burns 60W X 8700 hr/yr = 525600 watt-hours or 526 kilowatt-hours. If your electrical rate is the US-average of $0.12/kwh, that will cost you about $63.
Explanation:
@MNF
Answer:
600 J
Explanation:
P = E/T
60= E/10
60×10=E
600 Joules = E