Question

A 600 microferad capacitor is charged by 200 v supply . Ith is th3en disconected from the supply and is connected to another uncharged 600 microferad capacitor . How much the electrostatic energy is lost inthe process?

Answer 1

Solution:

Given,

Capacitance of capacitor, C = 600 microFarad

Potential difference, V = 200 V

By applying the formula of Electrostatic Energy,

Electrostatic Energy = 1/2 CV^2

Electrostatic Energy = 1/2 (600 × 10^-6) × (200)^2

Electrostatic Energy = 1.2 × 10 J

Electrostatic Energy = 12 J

Effective combination in 2nd case,

C' = 600 × 600/ 600 + 600 = 3600 / 1200 = 300 microFarad

Electrostatic Energy, E' = 1/2 CV^2

Electrostatic Energy = 1/2 (300 × 10^-6) × (200)^2

Electrostatic Energy = 0.6 × 10 J

Electrostatic Energy = 6 J

Loss in electrostatic energy = E - E'

Loss in electrostatic energy = 12 J - 6 J = 6 J

Thus, the electrostatic energy is lost in the process is 6 Joule.