Question

A 600pF capacitor is charged by a 200V supply .It is then disconnected from the supply and is connected to another uncharged 600pF capacitor. How much electrostatic energy is lost in the process. Please answer fast... If you don't know the correct answer then don't answer. I will report it.

Answer 1

Answer:

Initial energy, E=

2

1

CV

2

E=1.2×10

−5

J

when another capacitor is connected,

C

1

1

=

C

1

+

C

1

C

1

=300 pF

E

1

=

2

1

C

1

V

2

=0.6×10

−5

ΔE=E−E

1

=6×10

−6

J