Question

A 60g bullet fired from 5kg gun leaves with a speed of 500m/s.find the speed with which the gun recoils?

Answer 1

Given that
Mass of bullet = 60g =60/1000 = 0.06kg
Speed of the bullet = 500m/s
Mass of the gun= 5kg

According to the law of conservation of momentum
Momentum of bullet =momentum of gun
Mass of bullet × velocity of bullet = mass of the gun ×recoil of gun
0.06 × 500 = 5 × v
30 = 5v
v=30/5
v=6
So the recoil speed of the gun =6m/s

Answer 2

Answer:

firstly we has mass of bullet fired = 60g

convert to g in kg =60\1000= 0.06kg

And next we has mass of gun =5kg.

speed =500m/s.

we all know that = Total momentum of bullet = Total momentum of gun.

0.06×v = 5 ×500

0.006×v =2500

v= 2500÷0.06

6 m/s