A 60g bullet fired from a 5kg gun leaves with a speed of 500m/s. Find the velocity with which the gun recoils.
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Given,
Mass of bullet
= 60g
=60/1000
= 0.06kg
Speed of the bullet = 500m/s
Mass of the gun= 5kg
According to the law of conservation of momentum
Momentum of bullet = Momentum of gun
Mass of bullet × velocity of bullet = Mass of the gun × Recoil of gun
0.06 × 500 = 5 × v
30 = 5v
v=30/5
v=6
So, the recoil speed of the gun is 6m/s
✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️
Given,
Mass of bullet
= 60g
=60/1000
= 0.06kg
Speed of the bullet = 500m/s
Mass of the gun= 5kg
According to the law of conservation of momentum
Momentum of bullet = Momentum of gun
Mass of bullet × velocity of bullet = Mass of the gun × Recoil of gun
0.06 × 500 = 5 × v
30 = 5v
v=30/5
v=6
So, the recoil speed of the gun is 6m/s
✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️
Answered by
5
from conservation law of momentum
V=-mv/M
=-60×500/5
=-6000m/s
I hope this will helps you
V=-mv/M
=-60×500/5
=-6000m/s
I hope this will helps you
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