A 60kg body is pushed horizontally with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static and sliding friction are 0.5 and 0.4 respectively. The acceleration of the body?
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Let,F and f be the force of static friction and kinetic friction respectively.
And K and k be the corresponding coefficient of friction.
Let, the force applied be P and g be 10m/s²(For simpler calculation. You may change it to its original value if you want)
As, applied force P is just enough to make it move.
P = F (we know, we body is at rest w.r. to surface it's attic friction doing the job)
P = K(60)g = 300N
Now, the same force is being applied continuously. So, from the free body diagram of body we can conclude that
P - f = 60a (where a is acceleration)
300 - k(60)g =60a
a = 1m/s²
And K and k be the corresponding coefficient of friction.
Let, the force applied be P and g be 10m/s²(For simpler calculation. You may change it to its original value if you want)
As, applied force P is just enough to make it move.
P = F (we know, we body is at rest w.r. to surface it's attic friction doing the job)
P = K(60)g = 300N
Now, the same force is being applied continuously. So, from the free body diagram of body we can conclude that
P - f = 60a (where a is acceleration)
300 - k(60)g =60a
a = 1m/s²
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