A 60kg cart is accelerated from rest to 5 m/s in 2 seconds. If the applied force is 300/y N, find the value of y
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sorry bro don't know..
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Answer:
2
Explanation:
given mass m=60kg ,
we know f=ma_(1)
first we have to find accelaration,
here initial velocity (u) is given '0'
final velocity(v) =5m/s
and time (t) =2sec
from v=u+at
a=v-u/2
we have to substitite those values here
then, a=5/2 we will get
after wards put in (1)
given f=300/y
here, 300/y=60×5/2
300/y=300/2
comparing on both sides
y=2
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