A 60Kg man is inside a lift which is moving up with an acceleration of 2.45 m/sec2. The apparent percentage change in his weight is
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Given:
A 60Kg man is inside a lift which is moving up with an acceleration of 2.45 m/s².
To find:
Percentage change in his Weight.
Calculation:
Weight of the man in stationary lift be w1.
Weight of man in lift accelerating upwards be w2.
Change in weight be ∆w.
∆w = 747 - 600 = 147 N
So , final answer is :
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