Question

a 60kg man is inside a lift which is moving up with an acceleration of 2.45m/s2.the apparent percentage change in his weight is?

Answer 1

Answer:

its a question of pseudo force.

so first we have to find total pseudo force on man

we know that pseudo force applies in opposite direction of accn and equal to m×a.

so total pseudo force acting on him =60 ×2.45

=147 n

so

here g is accn due to gravity.

so total wight of man of man 60g+147

so change in weight 60g+147 -60g

=147

so %change in weight=147/60g ×100

taking g=10m/s^2

147/600 ×100

=147/6 %

=24.5%